[qwiz style=”width: 320px !important;”]
[q labels=”bottom”]
化合物中にHやOが含まれていれば,HやOの酸化数をもとにして他の原子の酸化数が計算できることを学びました。しかし,HやOが含まれていないときはどうすれば良いでしょうか。そのようなときは化合物をイオンに分けて②の約束を使えば良いのです。
たとえば食塩NaClは,Na+とCl–のイオンに分けられます。
Na+の酸化数は です。
これがそのままNaCl中のNaの酸化数になります。
同様にしてCl–の酸化数が NaCl中のClの酸化数になります。
[f*] Excellent!
[fx] Sorry, that’s not correct.
[f*] Excellent!
[fx] No.
[f*] Good!
[fx] Sorry, that’s not correct.
[f*] Great!
[fx] No.
[f*] Great!
[fx] No, that’s not correct.
[f*] Good!
[fx] No.
[q labels=”bottom”]
ヨウ化カリウムKIについて考えてみましょう。
KIはK+とI–のイオンに分けられます。
K+の酸化数は ,I–の酸化数は です。
したがってKI中のKとIの酸化数は,
K I
となります。
[f*] Excellent!
[fx] No, that’s not correct.
[f*] Correct!
[fx] No, that’s not correct.
[f*] Correct!
[fx] Sorry, that’s not correct.
[f*] Great!
[fx] No.
[f*] Excellent!
[fx] Sorry, that’s not correct.
[f*] Excellent!
[fx] No, that’s not correct.
[q labels=”bottom”]
Mg Cl2
[f*] Excellent!
[fx] No.
[f*] Great!
[fx] Sorry, that’s not correct.
[f*] Correct!
[fx] Sorry, that’s not correct.
[f*] Great!
[fx] No.
[f*] Correct!
[fx] No, that’s not correct.
[f*] Good!
[fx] No.
[q labels=”bottom”]
となります。
[f*] Great!
[fx] Sorry, that’s not correct.
[f*] Excellent!
[fx] Sorry, that’s not correct.
[f*] Good!
[fx] No, that’s not correct.
[f*] Correct!
[fx] No, that’s not correct.
[f*] Correct!
[fx] No, that’s not correct.
[f*] Good!
[fx] No, that’s not correct.
[f*] Good!
[fx] No, that’s not correct.
[f*] Good!
[fx] No, that’s not correct.
[q labels=”bottom”]
Al Cl3
[f*] Correct!
[fx] No, that’s not correct.
[f*] Great!
[fx] No, that’s not correct.
[f*] Correct!
[fx] Sorry, that’s not correct.
[f*] Good!
[fx] Sorry, that’s not correct.
[f*] Great!
[fx] No, that’s not correct.
[f*] Good!
[fx] No.
[q labels=”bottom”]
⑤過酸化物中のOの酸化数は-1
③の約束で化合物中のOの酸化数を
としましたが,
おぼえておけば良いでしょう。
過酸化水素 | 水 | |
H2O2 | ←→ | H2O |
+1 | +1 |
[f*] Excellent!
[fx] Sorry, that’s not correct.
[f*] Correct!
[fx] No.
[f*] Excellent!
[fx] No, that’s not correct.
[f*] Good!
[fx] No, that’s not correct.
[f*] Great!
[fx] No, that’s not correct.
[f*] Excellent!
[fx] Sorry, that’s not correct.
①単体を構成する原子の酸化数は0
④の約束から化合物中の原子の酸化数は, であり
⑥の約束からKMnO4中のKの酸化数は, です。このことより
K Mn O4
+Mn+ ×4=0
Mn=
となります。
[f*] Excellent!
[fx] No.
[f*] Great!
[fx] Sorry, that’s not correct.
[f*] Correct!
[fx] No, that’s not correct.
[f*] Great!
[fx] No, that’s not correct.
[f*] Great!
[fx] No.
[f*] Excellent!
[fx] No, that’s not correct.
[f*] Good!
[fx] No.
[f*] Great!
[fx] Sorry, that’s not correct.
[f*] Correct!
[fx] No.
[f*] Excellent!
[fx] No.
K2 Cr2 O7
×2+Cr×2+ ×7=0
Cr=
となります。
[f*] Excellent!
[fx] No.
[f*] Great!
[fx] Sorry, that’s not correct.
[f*] Correct!
[fx] No, that’s not correct.
[f*] Great!
[fx] No, that’s not correct.
[f*] Great!
[fx] No.
[f*] Excellent!
[fx] No, that’s not correct.
[f*] Good!
[fx] No.
[f*] Great!
[fx] Sorry, that’s not correct.
[f*] Correct!
[fx] No.
[f*] Excellent!
[fx] No.
[x]酸化と還元⑦酸化数の求め方2は,これでおわりです
つぎは酸化と還元⑧酸化数と反応です
[/qwiz]